Haskell XML - Get attribute value from node

I am making an XML parser in haskell. I have got the desired node using XPath, but I am confused that how can I get the attribute value of a node. Kindly assist me.

Here is my XML

xml = "<?xml version=\"1.0\" encoding=\"UTF-8\"?><root response=\"True\"><movie title=\"hulk\"/></root>"

I want to get 'title' attribute value.

{-# LANGUAGE Arrows, NoMonomorphismRestriction #-}
import Text.XML.HXT.Core
import Text.XML.HXT.XPath.Arrows 



data movie = movie { title :: String } deriving (Show, Eq)

xml = "<?xml version=\"1.0\" encoding=\"UTF-8\"?><root response=\"True\"><movie title=\"hulk\"/></root>"

main :: IO ()
main = do
      runX $ readString [] xml
            >>>
            root [] [ selem "values" [getXPathTrees "root/movie"]]
            >>>
            writeDocument [withIndent yes] "out.xml"
      return ()