My XML structure looks a bit like this:
<Bookmark>
<Type>Media</Type>
<Name>YouTube</Name>
<Link>http://ift.tt/1EVbjjJ;
</Bookmark>
<Bookmark>
...
</Bookmark>
...
What I want to do is to display in html a table where the bookmark Name
is displayed in a column according to the Type
of bookmark that it is (i.e. a column for media bookmarks, a column for work bookmarks etc) and that name is a link to the address provided by Link
.
This is what I have so far (modified from w3schools):
<script>
if (window.XMLHttpRequest)
{// code for IE7+, Firefox, Chrome, Opera, Safari
xmlhttp = new XMLHttpRequest();
}
else
{// code for IE6, IE5
xmlhttp = new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.open("GET","xml/bookmarks.xml",false);
xmlhttp.send();
xmlDoc = xmlhttp.responseXML;
document.write("<table>");
var x = xmlDoc.getElementsByTagName("Bookmark");
for (i = 0; i < x.length; i++)
{
document.write("<tr><td>");
if (x[i].getElementsByTagName("Type")[0].childNodes[0].nodeValue == "Social")
{
document.write(x[i].getElementsByTagName("Name"[0].childNodes[0].nodeValue);
document.write("</td></tr>");
}
}
document.write("</table>");
</script>
This displays all the social bookmarks as I wanted. The part I am struggling with is making the results a link and applying my CSS to them.
Maybe I am going about this the wrong way totally, any advice would be appreiciated (note: my next to do item is to allow a web based interface to add and delete bookmarks - is this possible using the same techniques as below or do I need to go into XQuery or something similar?)
No comments:
Post a Comment