How to select the right node value using xsl:if

I have 2 different XML

1 XML

<address>
    <localityType>CityType</localityType>
    <locality>CityName</locality>
</address>

2 XML

<address>
    <localityType>TownType</localityType>
    <locality>TownName</locality>
</address>

And I have a XSLT stylesheet

...

<table border="1" cellpadding="2" cellspacing="0">
    <tr>
        <td>City</td>
        <td>
            <xsl:variable name="loc" select="//localityType"/>
            <xsl:if test="loc == 'CityType'">
                <xsl:value-of select="//locality" />
            </xsl:if>
        </td>
    </tr>
    <tr>
        <td>Town</td>
        <td>
            <xsl:variable name="loc" select="//localityType"/>
            <xsl:if test="localityType != 'CityType'">
                <xsl:value-of select="//locality" />
            </xsl:if>
        </td>
    </tr>
</table>

...

And as the result I want to get for the first XML the following table

And as the result for the second XML - the following table