XSL copy parent nod of attribute node

I want to copy the attribute node and the parent of the corresponding element node. How do I get the parent of the elementnode of an attribute node? I have a sample XML File:

<?xml version="1.0" encoding="UTF-8"?>
<XML>
    <Items ID = 'ID'>
        <Item OID='haveit'></Item>
        <Item OID='ornot'></Item>
    </Items>
</XML>

I want this file to transform to:

<?xml version="1.0" encoding="UTF-8"?>
<XML>
    <Items ID = 'ID'>
        <Item OID='haveit'></Item>
    </Items>
</XML>

What I have so far:

<xsl:stylesheet version="2.0" xmlns:xsl="http://ift.tt/tCZ8VR">
    <xsl:output method="xml" version="1.0" encoding="utf-8" indent="yes" />
    <xsl:strip-space elements="*" />

    <xsl:template match="XML">
        <xsl:copy>
            <xsl:apply-templates/>
        </xsl:copy>
    </xsl:template>

    <xsl:template match="Item[@OID = 'haveit']">
        <!-- copy parent with all attributes -->
        <xsl:copy-of select="." />
    </xsl:template>
</xsl:stylesheet>

With this I'm able to copy the XML root Element and the Item 'haveit'. What I now need is to copy the Items element with the ID attribute.