I need detect dynamically which is the spring profile send it in setenv.bat
My setenv.bat has
set "JAVA_OPTS= -Dspring.profiles.active=dev" and in web.xml has
<context-param> <param-name>spring.profiles.active</param-name> <param-value>${spring.profiles.active}</param-value> </context-param> but doesn't works.
Other way is using profile tag in xml
<?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:int="http://www.springframework.org/schema/integration" xmlns:int-http="http://www.springframework.org/schema/integration/http" xmlns:context="http://www.springframework.org/schema/context" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd http://www.springframework.org/schema/integration http://www.springframework.org/schema/integration/spring-integration.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd http://www.springframework.org/schema/integration/http http://www.springframework.org/schema/integration/http/spring-integration-http.xsd" profile="${spring.profiles.active}"> . . . . </beans> but doesn't works too
I am using spring 4.1.5 release
I don't know how can I get it, how can I?
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