XML : how to add tag to transformed xml using xslt?

i want to transform this xml to another xml using xslt. i have use this code for transformation.

  result = new XSLTProcessor();  result.importStylesheet(xsl);  result = result.transformToDocument(xml);    

this code working fine. but resultant xml doesn't contain <?xml version="1.0" encoding="UTF-8"?>

i intentionally removed <?xml version="1.0" encoding="UTF-8"?> from input xml. xml:-

  <rentalProperties>      <property contact="1">          <type>House </type>          <price>420</price>          <address>              <streetNo>1</streetNo>              <street>Wavell Street</street>              <suburb>Box Hill</suburb>              <state>VIC</state>              <zipcode>3128</zipcode>          </address>          <numberOfBedrooms>3</numberOfBedrooms>          <numberOfBathrooms>1</numberOfBathrooms>          <garage>1</garage>      </property>  </rentalProperties>    

xsl:-

  <?xml version="1.0" encoding="UTF-8"?>  <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">      <xsl:output omit-xml-declaration="no" indent="yes"/>   <xsl:strip-space elements="*"/>     <xsl:template match="node()|@*">    <xsl:copy>     <xsl:apply-templates select="node()|@*"/>    </xsl:copy>   </xsl:template>     <xsl:template match="address">    <xsl:copy>     <xsl:value-of select=     "concat(streetNo, ' ', street, ',',             suburb,',', state,', Australia')     "/>    </xsl:copy>   </xsl:template>   <xsl:template match="address/node()"/>  </xsl:stylesheet>    

i want to add <?xml version="1.0" encoding="UTF-8"?> to transformed xml. is there any way to add using xslt or copy this tag to output xml.

please give any suggestion .